# Can You Crack This Code To Open Mobile Phone? Puzzle ID: oj1a7

This is a new crack the code cipher puzzle. This cipher puzzle is for teens who are interested in solving this kind of brainy puzzles.

## Puzzle ID: oj1a7

7 9 3 1 4 – 1 number is correct but in the wrong position.
9 5 6 4 3 – 2 numbers are correct but only one in the right position.
5 7 3 1 9 – 2 numbers are correct And in the right position.

Sum of the numbers is equal to last two digits.
i.e. if numbers are A, B, C, D, E then A + B + C + D + E = D*10 + E

1. Lk mishra says:

No conditions given on restriction of using any other no.. need to fulfill the condition given

57628

1st..7 in wrong position
2nd.. 5 in wrong position
6 in right position
3rd .. 5&7 both in right position

1. Anonymous says:

but that couldn’t be it because 5+7+6+2+8 doesn’t equal 2*10 + 8

1. Martin Beres says:

5+7+6+2+8 =28 = 2 X 10 + 8

2. Martin Beres says:

The solution doesn’t appear to be unique. I believe 57620, 57622 and 57628 all meet the terms of the clues.