This is a new crack the code cipher puzzle. This cipher puzzle is for teens who are interested in solving this kind of brainy puzzles.

## Puzzle ID: oj1a7

7 9 3 1 4 – 1 number is correct but in the wrong position.

9 5 6 4 3 – 2 numbers are correct but only one in the right position.

5 7 3 1 9 – 2 numbers are correct And in the right position.

Sum of the numbers is equal to last two digits.

i.e. if numbers are A, B, C, D, E then A + B + C + D + E = D*10 + E

You can check your answer here.

## Answer:

This puzzle has not yet been solved by anyone.

No conditions given on restriction of using any other no.. need to fulfill the condition given

So answer is

57628

1st..7 in wrong position

2nd.. 5 in wrong position

6 in right position

3rd .. 5&7 both in right position